1 条题解
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0
C++ :
#include<bits/stdc++.h> using namespace std; int n,k,ans,z; int main() { cin>>n>>k; for (int i=1;i<=k;i++)z+=i; for (int i=1;i<=n-k;i++) { z+=k; // cout<<z<<endl; if (floor(sqrt(z))==sqrt(z))ans+=1; } cout<<ans; return 0; }
Pascal :
var n, k, sum, i, t, ct:longint; begin readln(n,k); sum := 0; ct := 0; for i := 1 to k do sum := sum + i; t := trunc(sqrt(sum)); if t * t = sum then inc(ct); for i := 2 to n - k + 1 do begin sum := sum+ k; t := trunc(sqrt(sum)); if t * t = sum then inc(ct); end; writeln(ct); end.
- 1
信息
- ID
- 1156
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者